>>30371408>If you could dumb this down more I’d be grateful.I can dumb down some of it, the basics of what i'm hinting at is pretty simple. The complex part is finding the formulas and implications.

Start with dividing by zero; why can't we? The common answer you'll get is that it "doesn't make sense." Let's look at why:

First we can approach zero (from both positive and negative values) using f(x) = 1/x. What happens when we have 1/0.1? It becomes 10. How about 1/0.01? It becomes 100.

The closer we get to zero, the larger our answer becomes (as we approach zero, we approach infinity). If we approach from the negative size (1/-0.1) we approach negative infinity.

Thus 1/0 can be positive OR negativity infinity, BOTH ARE TECHNICIALLY VALID (key starting idea) even though it doesn't make sense mathematically thus overlooked.

So let's now look at 0/0. We can approach this in two ways: we can approach zero using: f(x) = x/x and use smaller and smaller numbers, and we can also approach zero using f(x)=0/x (kinda like our 1/0 example above).

Using f(x)=x/x we can start plugging in values, likes 0.001, -0.00001, 0.0000001, etc... and what we'll find is that it'll end up evaluating to 1 every time. So f(x)=x/x=1 should hold true.

Now lets let the denominator approach zero instead. Whether we have 0/0.1 or 0/-0.00000000001, it's going to evaluate to 0, so f(x)=0/x=0.

Now plug 0 into both f(x)s. What you'll get is: f(0)=x/x=0/0=1 and f(0)=0/x=0/0=0. Thus 0/0 can zero OR one (BOTH ARE EQUALLY VALID) and, once again, this doesn't make sense mathematically so we consider it undefined.

This is just the tiniest scratch of the surface of what I'd like more people to realize, but the next steps involve a lot of grunt, math work as well as really analyzing what in the fuck the function is ACTUALLY doing as well as knowing each input and limits of those parameters for the function (i.e. terminal velocity of a vacuum, setting the air density to 0 allows it to be undefined